离谱操作,离职后被前公司调查去向...

func rotate(matrix [][]int) {  n := len(matrix)
  // Transpose the matrix  for i := 0; i < n; i++ {    for j := i; j < n; j++ {      matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]    }  }
  // Reverse each row  for i := 0; i < n; i++ {    for j, k := 0, n-1; j < k; j, k = j+1, k-1 {      matrix[i][j], matrix[i][k] = matrix[i][k], matrix[i][j]    }  }}

public void rotate(int[][] matrix) {    int n = matrix.length;        // Transpose the matrix    for (int i = 0; i < n; i++) {        for (int j = i; j < n; j++) {            int temp = matrix[i][j];            matrix[i][j] = matrix[j][i];            matrix[j][i] = temp;        }    }        // Reverse each row    for (int i = 0; i < n; i++) {        for (int j = 0; j < n / 2; j++) {            int temp = matrix[i][j];            matrix[i][j] = matrix[i][n - 1 - j];            matrix[i][n - 1 - j] = temp;        }    }}

function rotate(matrix) {    let n = matrix.length;        // Transpose the matrix    for (let i = 0; i < n; i++) {        for (let j = i; j < n; j++) {            let temp = matrix[i][j];            matrix[i][j] = matrix[j][i];            matrix[j][i] = temp;        }    }        // Reverse each row    for (let i = 0; i < n; i++) {        matrix[i].reverse();    }}

def rotate(matrix):   n = len(matrix)   # Transpose the matrixfor i in range(n):    for j in range(i, n):        matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]
# Reverse each rowfor row in matrix:    row.reverse()

[  [1, 2, 3],  [4, 5, 6],  [7, 8, 9]]

[  [7, 4, 1],  [8, 5, 2],  [9, 6, 3]]